(2x)^2/(0.2-2x)(0.4-x)=0.0078

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Solution for (2x)^2/(0.2-2x)(0.4-x)=0.0078 equation: 



(2x)^2/(0.2-2x)(0.4-x)=0.0078

We move all terms to the left:

(2x)^2/(0.2-2x)(0.4-x)-(0.0078)=0



Domain of the equation: (0.2-2x)(0.4-x)!=0

We move all terms containing x to the left, all other terms to the right

-2x)(0.4-x!=-0.2

x∈R



We add all the numbers together, and all the variables

2x^2/(-2x+0.2)(-1x+0.4)-(0.0078)=0

We add all the numbers together, and all the variables

2x^2/(-2x+0.2)(-1x+0.4)-0.0078=0

We multiply parentheses ..

2x^2/(+2x^2-0.8x-0.2x+0.08)-0.0078=0

We multiply all the terms by the denominator


2x^2-(0.0078)*(+2x^2-0.8x-0.2x+0.08)=0

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